Sorry for X-Posting but needing help quickly, hopefully someone can assist.
The problem:
Two voltages v1 and v2 are to be summed using an analogue circuit.
v1 = 5 cos (5 pi t + (pi

*/ 6)) v2 = 10 sin (5 pi t - (pi /*6)) Calculate the time at which the sum is first equal to 4 volts. I have added the two voltages and left the result in R = sin (wt + a) and was calculated in radians w = omega a = alpha My answer to the sum is 11.18 sin (5 pi t + 1.63) Now, how do I find the time when the voltage is first equal to 4 volts. Appreciate any help. TIA